Monday, July 27, 2009

I am Really in Need of this by Today.... ( C Language Program - a simple one )?

A class of 35 Students takes an examination in which marks range is from 0 to 10. Write a Program which finds:





a) the average marks


b) the numberof students failed ( marks below 50 )


c) the number of students who scored 100 marks





::: Please if some one can help me in creating this program using a very simple C language its for my class tomorrow.





Try to use ( if else, else if, switch, while, do while......please! remember not too advanced... )





Thanks...


Waiting and in a hurry!!!!

I am Really in Need of this by Today.... ( C Language Program - a simple one )?
First you have to make an array to hold the marks for 35 students, say int student_mark[35].





Then you can use a for loop to read in the marks using scanf. You can also use a for loop to find the average mark.





You could also use a for loop to find b and c with if statements. For example, initializing below_50 and num_scored_100 = 0.


for(int i=0, i%26lt;35, i++)


{


if(student_mark[i] %26lt; 50)


below_50 ++;





else if(student_mark[i] == 100)


num_scored_100 ++;


}


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