making 3rd bit 0 in 8bit number without using following method 8-bit number %26amp; (11111011) in c language
Making 3rd bit 0 in 8bit number without using following method 8-bit number %26amp; (11111011) in c language?
number %26amp;= 0xfb;
Reply:(number / 16) * 16 + number % 8
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